Support Board
Date/Time: Fri, 31 Oct 2025 21:29:50 +0000
Post From: Code help, using a string instead of a constant
| [2023-08-27 20:32:52] |
| ondafringe - Posts: 328 |
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I'm looking at this link for pointers: https://www.programiz.com/cpp-programming/pointers But, yeah, this is pretty confusing stuff. lol However, maybe the reason you are only getting the first formula is because you are trying to redeclare a const within the for loop. I don't believe that is allowed, unless you first drop out of the for loop. Have you tried declaring Formula like this, leaving const out: char* Formula I just looked at sc.EvaluateGivenAlertConditionFormulaAsDouble and it does show "const SCString& Formula" as the third argument, so the above probably won't work. Date Time Of Last Edit: 2023-08-27 20:46:36
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